Quantitative Methods in Social Science 360-300 • CEGEP, Montreal

Corrected exercises: sampling and questionnaires (360-300)

These ten corrected exercises for Quantitative Methods, 360-300, the CEGEP course in the Social Science program, deal with everything that is decided BEFORE the data are collected: which list we draw from, how we draw, how many we draw, and how we word what we ask. You work on the target population and the sampling frame, undercoverage and overcoverage, probability sampling plans (simple random, systematic, stratified, cluster) and nonprobability plans (quota, convenience, purposive, snowball), the design effect, the required sample size and the finite population correction, proportional and Neyman allocation, the wording of a questionnaire and nonresponse bias.

By the end of the set, you can spot the coverage defect of a sampling frame (exercise 1), compute the step of a systematic sample and the effective size of a cluster sample (exercise 2), say what a quota sample allows you to conclude and what it does not (exercise 3), compute the sample size required for a given margin of error (exercise 4), split questionnaires among strata (exercise 5), fix a double-barrelled question, a leading question or badly cut response categories (exercise 6) and estimate nonresponse bias from a follow-up (exercise 7). The two problems design a survey of CEGEP student life from start to finish (exercise 9) and explain two polls from the same month that give 54% and 41% (exercise 10).

The thread of the set fits in one sentence: sample size only reduces the error due to chance, and every other error, coverage, selection, nonresponse, wording, is already written into the plan before a single questionnaire goes out.

Three traps are named explicitly: the rule of ten percent of the population (exercises 4 and 8), the margin of error announced for a quota sample (exercises 3 and 8), and the raw size of a cluster sample used as is in the formulas (exercises 2 and 8). The solutions also point out that a good response rate does not prove representativeness (exercises 7 and 8).

10 corrected exercises • 100 points • 150 minutes

This chapter is part of 360-300, every chapter with its set and sheet Before you start Revision sheet: the traps and the method for this chapter

Self-checking set Type your answers and check them question by question: the page tells you right or wrong before you open the solution. With an account, every answer right on the first try earns points, and your right answers stay filled in when you come back.

Course recap

  • • TARGET POPULATION, SAMPLING FRAME, SAMPLE. Undercoverage: in the population, missing from the frame, so a zero probability of inclusion. Overcoverage: in the frame, outside the population.
  • • A plan is PROBABILITY-BASED if every unit has a known, nonzero probability of being drawn. Known, not necessarily equal: weights correct for it afterwards.
  • • Four probability plans: simple random, systematic (step k=Nnk=\dfrac{N}{n}), stratified (we draw within every stratum), cluster (we draw entire blocks).
  • • At equal size, stratified sampling is more precise than simple random sampling; cluster sampling is less precise, because the members of a cluster resemble one another.
  • • DESIGN EFFECT: effective sample size neff=ndeffn_{eff}=\dfrac{n}{deff}. It is neffn_{eff}, not nn, that goes into any margin-of-error formula.
  • • Nonprobability plans: quota, convenience, purposive, snowball. None gives a margin of error, and weighting does not turn them into one.
  • • Required size for a proportion: n=z2p(1−p)E2n=\dfrac{z^{2}p(1-p)}{E^{2}}, with z=1.96z=1.96 at 95%. With no information we take p=0.5p=0.5, because p(1−p)p(1-p) is largest there.
  • • Finite population correction: nc=n1+n−1Nn_{c}=\dfrac{n}{1+\dfrac{n-1}{N}}, useful as soon as the sample exceeds about 5% of the population.
  • • PROPORTIONAL allocation: according to NhN_{h}. NEYMAN allocation: according to NhshN_{h}s_{h}, so more questionnaires where the stratum is spread out.
  • • Questionnaire faults: double-barrelled question, leading question, response categories that are not exhaustive or not mutually exclusive, order effect, social desirability.
  • • Nonresponse bias: (1−t)(y‾r−y‾nr)\left(1-t\right)\left(\overline{y}_{r}-\overline{y}_{nr}\right). The response rate measures the risk, never the bias itself.

Part A: the basics (/50)

Exercise 1: Target population, sampling frame and coverage

Before anyone can be drawn, you need a LIST to draw from. That list, the sampling frame, never coincides exactly with the population we are aiming at, and it is in the gap between the two that errors live which no calculation will ever make up for.

target populationsampling framesampleunder-coverageovercoverage
  • a) Define target population, sampling frame, undercoverage and overcoverage, using the diagram.
  • b) A survey aims at the adults of Quebec and draws from the directory of landline telephone numbers. Name the undercoverage and the overcoverage, and say which group is the worst represented.
  • c) We want to survey the students of a CEGEP and we use the list of students registered for the fall term for a survey carried out in April. What coverage defect does this create?
  • d) One household has two telephone lines, another has only one. Are their probabilities of being reached equal? What do we do about this inequality?
  • e) Can we increase the sample size to correct a coverage defect? Justify in one sentence that you could write on the board.

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  • a) Target population, sampling frame, undercoverage (missing from the frame) and overcoverage (in the frame but out of scope)
  • b) Undercoverage: people without a landline, above all young adults. Overcoverage: businesses, lines out of service
  • c) Undercoverage of the winter newcomers AND overcoverage of the leavers; the two errors push in the same direction
  • d) No, the ratio is 22; a probability-based plan requires KNOWN probabilities, and we weight by 12\dfrac{1}{2}
  • e) No: enlarging nn reduces the random error as 1n\dfrac{1}{\sqrt{n}}, never a zero coverage
a)

The TARGET POPULATION is the set of units about which we want to conclude, here decided by the research question and not by the means available. The SAMPLING FRAME is the concrete list in which the draw takes place. UNDERCOVERAGE refers to the members of the target population that are missing from the frame: they have a ZERO probability of being chosen, whatever we do afterwards. OVERCOVERAGE refers to the elements of the frame that do not belong to the target population: duplicates, outdated units, people outside the scope. A survey strictly speaks only about the intersection, the middle zone of the diagram, and anything said beyond it rests on a wager.

b)

Undercoverage: adults without a landline, which today means the majority of people under 45, recently moved households, some tenants and people on low incomes. Overcoverage: numbers assigned to businesses, lines that are out of service and residents under 18 who pick up the phone. The worst represented group is by far that of YOUNG ADULTS, whose exclusion is almost systematic: since their opinions often differ from those of older people on political and social subjects, the resulting error is directional and not random. That is why serious polling firms now combine landlines, cell phones and panels, with known inclusion rates for each source.

c)

The fall list ignores the students enrolled for the first time in the winter term, and keeps those who dropped out between the two terms. We therefore get undercoverage, the newcomers, and overcoverage, the leavers, at the same time. The defect is especially troublesome if the survey is about persistence: the dropouts, overrepresented in the frame, are precisely the hardest to reach, so coverage error and nonresponse push in the same direction.

d)

No, they are not equal: the household with two lines has two chances of being drawn, so roughly double the probability. A probability-based plan does not require the probabilities to be EQUAL, it requires them to be KNOWN and nonzero. We therefore correct at the analysis stage, by giving each unit a weight inversely proportional to its probability of inclusion: the household with two lines counts for one half. The same principle governs stratified plans with unequal sampling rates.

e)

No. A sentence to remember: enlarging the sample multiplies the respondents we already had the means to reach, and does not make anyone appear in a list where they are not listed. A zero probability of inclusion stays zero however many draws we make. Increasing nn reduces the RANDOM error, as 1n\dfrac{1}{\sqrt{n}}; coverage error is SYSTEMATIC and depends only on the frame. The only remedy is to change the frame or to combine several.

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Exercise 2: Probability sampling plans: strata, clusters and design effect

Four probability plans are enough to cover almost every survey in the social sciences. They do not differ in honesty, all of them are probability-based, but in what they cost and in the precision they return for that cost.

stratifiedcluster
  • a) Describe each of the four plans in one sentence: simple random, systematic, stratified, cluster.
  • b) A CEGEP has 6,200 students spread over 5 programs. We want 300 respondents. Give the step of a systematic sample, and the size of each stratum under proportional allocation if the programs weigh 38%, 24%, 18%, 12% and 8%.
  • c) Why is the STRATIFIED plan generally more precise than simple random sampling of the same size, and the CLUSTER plan less precise?
  • d) We draw 12 class groups out of 210 and survey all of their students, 336 in all. The ratio of the variance obtained to that of a simple random sample of the same size is 1.9. How many students in a simple random sample would give the same precision?
  • e) When does systematic sampling become dangerous? Give a specific example.

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  • a) Simple random, systematic (one in kk), stratified (we draw in all the groups), cluster (we draw groups)
  • b) k≈20.67k\approx 20.67, rounded down to 2020; sizes 114114, 7272, 5454, 3636, 2424, summing to 300300
  • c) Stratifying removes the chance of the composition; in clusters, neighbours resemble one another and bring less information
  • d) Design effect 1.91.9: neff=3361.9≈177n_{eff}=\dfrac{336}{1.9}\approx 177; we would need 638638 students in clusters to match 336336
  • e) When the list is periodic and the step always lands in the same place; we check or shuffle the list
a)

SIMPLE RANDOM: every member of the frame has the same probability of being drawn and every group of size nn is equally possible. SYSTEMATIC: we draw a starting point at random among the first kk, then take one unit out of every kk in the list. STRATIFIED: we first split the population into homogeneous and exhaustive groups, the strata, then draw within EACH one. CLUSTER: we split the population into natural blocks, we draw BLOCKS, and we survey everyone inside the selected blocks. The decisive difference between the last two is in the diagram: stratified sampling draws within all the groups, cluster sampling draws groups.

b)

Step of the systematic sample: k=6,200300≈20.67k=\dfrac{6{,}200}{300}\approx 20.67, rounded down to 20, which will give a sample slightly larger than 300 that we adjust at the end. Proportional allocation: 0.38×300=1140.38\times 300=114, 0.24×300=720.24\times 300=72, 0.18×300=540.18\times 300=54, 0.12×300=360.12\times 300=36, 0.08×300=240.08\times 300=24. The sum is indeed 300, and that is the check to make every time, because a badly placed rounding is the most frequent error on this type of question.

c)

Stratified sampling wins because the total variance splits into WITHIN-stratum variance and BETWEEN-strata variance: by imposing the right sizes in each stratum, we completely eliminate the part of the error due to the chance of the sample's composition, and only the variability inside the strata remains. The gain is larger the more homogeneous the strata are internally and the more they differ from one another. Cluster sampling suffers exactly the opposite mechanism: the members of one cluster resemble one another, a class, a building, a neighbourhood, so that the twelfth student of a class already surveyed brings much less new information than a student drawn at random from the whole CEGEP. We pay in precision for what we save in travel.

d)

The ratio 1.9 is the DESIGN EFFECT. The effective size is neff=3361.9≈177n_{eff}=\dfrac{336}{1.9}\approx 177 students: the 336 students grouped into 12 classes are worth, in precision, about 177 students drawn at random one by one. This is the number to use in any margin-of-error formula, otherwise we announce a precision the survey does not have. Conversely, to obtain the precision of a simple random sample of 336, we would need here 336×1.9≈638336\times 1.9\approx 638 students in clusters.

e)

Systematic sampling becomes dangerous when the list contains a PERIODICITY whose period is a multiple or a divisor of kk. A specific example: a list of students arranged class by class, each class having exactly 30 names and the first name of each class being the class representative; with a step of 30, we survey only representatives. Another classic example: a daily sales record sampled one day in seven, which always falls on the same day of the week. The remedy is to check the order of the list before drawing, or to shuffle it deliberately.

Exercise 3: Nonprobability plans, and when they are legitimate

Most of the surveys actually carried out in the social sciences are not probability-based: neither the budget, nor the field, nor sometimes ethics allows it. That does not make them worthless, it changes what we are entitled to conclude from them.

  • a) Describe QUOTA, CONVENIENCE, PURPOSIVE and SNOWBALL sampling.
  • b) Quota sampling looks a lot like stratified sampling. Name the one difference, and explain why it is enough to change everything.
  • c) To study the life paths of people experiencing homelessness, a researcher recruits by snowball. Justify this choice, then name the population the researcher risks missing.
  • d) A professor has his three quantitative methods groups fill in a questionnaire and writes: “a sample of 96 CEGEP students”. Rewrite the sentence correctly.
  • e) A polling firm claims that with good weighting, a panel of volunteers is as good as a probability sample. How should you answer?

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  • a) Quota (cells to fill), convenience (whoever is available), purposive (informative cases), snowball (through the network)
  • b) Stratified sampling draws at random within the stratum, quotas let the interviewer choose: no known probability, so no margin of error
  • c) No sampling frame exists for this population; the method misses isolated people, with no network
  • d) “Convenience sample of 96 students enrolled in three quantitative methods groups, winter term”
  • e) Weighting corrects the composition, never the selection: a volunteer stays a volunteer inside the cell
a)

QUOTA: the interviewer is required to fill cells, for example 40 women aged 18 to 34, and recruits whoever they like to fill them. CONVENIENCE, or accidental: we interview the people who are available, at the exit of a shopping mall, in our own class, on a social network. PURPOSIVE, or judgment sampling: the researcher deliberately selects cases judged informative, typical cases, extreme cases, contrasting cases, which is common in qualitative research. SNOWBALL: the first participants recruit the next ones from their network, a procedure reserved for rare or hard-to-reach populations.

b)

The only difference is the mode of selection INSIDE the groups: stratified sampling draws AT RANDOM in each stratum, quota sampling lets the interviewer CHOOSE who fills the cell. The consequence is total: without a random draw, no inclusion probability is known, so no sampling theory applies, so neither a margin of error nor a confidence interval can be computed. And the interviewer's choice is never neutral: with identical quotas, they will approach people who are available, pleasant and present during business hours. The structure will be right and the selection biased.

c)

Snowball sampling is justified here because there is no sampling frame of people experiencing homelessness: no list, no address, no telephone line, and a legitimate distrust of institutions. The participants' network is then the only way in. What it risks missing: precisely the ISOLATED people, with no network, who are often the most vulnerable, as well as the segments that never come into contact with the first people recruited, for example women housed by acquaintances rather than on the street. The method explores the network, not the population, and the report must say so.

d)

“Convenience sample of 96 students enrolled in three quantitative methods groups at the CEGEP, in the winter term.” What changes is not cosmetic: the wording names the plan, so it announces the absence of a margin of error, and it names the population actually reached, which is not the CEGEP but the students enrolled in one given course. The results are still publishable and instructive; they describe these 96 students and suggest hypotheses, they do not estimate anything.

e)

You must answer that weighting corrects the observable COMPOSITION and never the SELECTION. Reweighting by age, sex, region and education aligns the proportions of the sample with those of the census, which is useful; but inside each cell, the volunteers of a panel remain volunteers, that is, people more interested in surveys, more available and often more politicized than those they are supposed to represent. No weighting variable measures this difference, and weighting on more variables only moves the problem. A well-run panel is a good tool for comparison over time, with a constant mode; it does not become a probability sample for that.

Exercise 4: What sample size do we really need?

Size is computed from the precision wanted, never from the size of the population. It is the most counterintuitive result of the chapter, and the most useful.

We want to estimate a proportion at the 95% level, for which z=1.96z=1.96, with the formula n=z2p(1−p)E2n=\dfrac{z^{2}p(1-p)}{E^{2}}.

  • a) Compute nn for a margin of 3 percentage points, then of 2 points, taking p=0.5p=0.5. Comment on the ratio between the two.
  • b) Why do we take p=0.5p=0.5 when we know nothing? Show it by comparing p(1−p)p(1-p) for p=0.5p=0.5 and p=0.2p=0.2.
  • c) A preliminary study indicates p≈0.2p\approx 0.2. Recompute nn for a margin of 3 points and say what the information saved.
  • d) The CEGEP has 6,200 students. Apply the finite population correction nc=n1+n−1Nn_{c}=\dfrac{n}{1+\dfrac{n-1}{N}} to the result of question a) for 3 points.
  • e) A colleague wants “10% of the population” whatever the question. How do you answer, comparing a CEGEP of 6,200 students with the whole of Quebec?

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  • a) n≈1,067n\approx 1{,}067 for 33 points, 2,4012{,}401 for 22 points; the ratio is (32)2=2.25\left(\dfrac{3}{2}\right)^{2}=2.25
  • b) Because p(1−p)p(1-p) is at its maximum at p=0.5p=0.5: 0.250.25 against 0.160.16 for p=0.2p=0.2
  • c) n=3.8416×0.160.0009≈683n=\dfrac{3.8416\times 0.16}{0.0009}\approx 683, against 1,0671{,}067: the prior information saves about 384384 respondents
  • d) nc=10671+10666200≈910n_{c}=\dfrac{1067}{1+\dfrac{1066}{6200}}\approx 910, that is 157157 respondents saved
  • e) The rule has no basis: the margin depends on nn, not on nN\dfrac{n}{N} once the population is large
a)

For E=0.03E=0.03: n=1.962×0.250.032=0.96040.0009≈1,067n=\dfrac{1.96^{2}\times 0.25}{0.03^{2}}=\dfrac{0.9604}{0.0009}\approx 1{,}067. For E=0.02E=0.02: n=0.96040.0004≈2,401n=\dfrac{0.9604}{0.0004}\approx 2{,}401. The ratio is 24011067≈2.25=(32)2\dfrac{2401}{1067}\approx 2.25=\left(\dfrac{3}{2}\right)^{2}: dividing the margin by 1.5 multiplies the size by 1.5 squared. The margin decreases as 1n\dfrac{1}{\sqrt{n}}, so the size grows as the square of the precision demanded, and that is what makes very precise surveys prohibitively expensive.

b)

Because p(1−p)p(1-p) is at its MAXIMUM at p=0.5p=0.5. Indeed 0.5×0.5=0.250.5\times 0.5=0.25 whereas 0.2×0.8=0.160.2\times 0.8=0.16. The function p↦p(1−p)p\mapsto p(1-p) is a downward-opening parabola with roots 0 and 1, so its vertex is halfway. Choosing p=0.5p=0.5 therefore means placing ourselves in the worst case: the size obtained guarantees the margin wanted whatever the true proportion. It is a prudent decision, not an estimate.

c)

n=1.962×0.160.0009=0.6146560.0009≈683n=\dfrac{1.96^{2}\times 0.16}{0.0009}=\dfrac{0.614656}{0.0009}\approx 683. The prior information brings the requirement down from 1,067 to 683 respondents, about 384 questionnaires saved, nearly a third of the budget. Beware of a calculation trap: the 0.9604 of question a) already contains p(1−p)=0.25p(1-p)=0.25, so we do not multiply it by 0.16, we start again from 1.962=3.84161.96^{2}=3.8416. Beware of the substance as well: if the true proportion turned out to be close to 0.5, the real margin would be much wider than 3 points. We take this risk only when the prior estimate is solid.

d)

nc=10671+10666200=10671.17194≈910n_{c}=\dfrac{1067}{1+\dfrac{1066}{6200}}=\dfrac{1067}{1.17194}\approx 910. The correction saves about 157 respondents, because a draw without replacement in a population of 6,200 uses up a non-negligible share of the information available. The usual rule is to apply it as soon as the sample exceeds about 5% of the population, which is largely the case here with 17%.

e)

The 10% rule has no basis. At the CEGEP, 10% of 6,200 is 620 respondents, fewer than the 910 that a margin of 3 points requires (it would give a margin of about 3.7 points); at the scale of Quebec, 10% would mean about 900,000 people for a precision that 1,067 already reach. The point to get across is that the margin of error depends on nn and practically not on NN once the population is large: it is the absolute size of the sample that counts, not its share. One spoonful is enough to taste the soup, whether the pot is small or large, as long as it has been stirred.

123456200040006000800010000E = 3: n = 1,067E = 2: n = 2,401margin E (points)required n

Exercise 5: Allocation in a stratified plan

A stratified plan still leaves one decision: how many respondents in each stratum. Two answers exist, and they do not serve the same objective.

A CEGEP of 6,200 students has to split 300 questionnaires among three sectors.

SectorSize NhN_{h}Standard deviation shs_{h} (hours of study)
Pre-university3,7204.0
Technical1,8606.0
Tremplin DEC6209.0
  • a) Compute the PROPORTIONAL allocation of the 300 questionnaires.
  • b) Compute the NEYMAN allocation, which splits according to the products NhshN_{h}s_{h}.
  • c) Compare the two for the Tremplin DEC sector and explain the difference by the logic of each method.
  • d) The college also wants to publish a separate result for Tremplin DEC, with a margin of error of at most 8 points. How many respondents are needed in this stratum, if p=0.5p=0.5? What happens to the allocation then?
  • e) Explain why the allocation that gives the best OVERALL estimate is not the one that allows the sectors to be compared with one another.

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  • a) Weights 0.600.60, 0.300.30, 0.100.10: 180180, 9090 and 3030 questionnaires
  • b) Products 14,88014{,}880, 11,16011{,}160, 5,5805{,}580, summing to 31,62031{,}620: 141141, 106106 and 5353
  • c) Tremplin DEC goes from 3030 to 5353: Neyman invests where the spread is large (s=9s=9 against 44)
  • d) n≈150n\approx 150, brought down to 121121 by the correction on 620620; 179179 remain for the other two sectors
  • e) Estimating the whole pushes toward weight and spread; comparing requires a size in EACH sector
a)

The weights are 37206200=0.60\dfrac{3720}{6200}=0.60, 18606200=0.30\dfrac{1860}{6200}=0.30 and 6206200=0.10\dfrac{620}{6200}=0.10. Proportional allocation therefore gives 180180, 9090 and 3030 questionnaires. The sum is 300, and each stratum is represented in the sample as it is in the population.

b)

Products NhshN_{h}s_{h}: 3720×4=14,8803720\times 4=14{,}880, 1860×6=11,1601860\times 6=11{,}160, 620×9=5,580620\times 9=5{,}580. Their sum is 31,62031{,}620. Neyman allocation: 300×1488031620≈141300\times \dfrac{14880}{31620}\approx 141, 300×1116031620≈106300\times \dfrac{11160}{31620}\approx 106, 300×558031620≈53300\times \dfrac{5580}{31620}\approx 53. The sum is indeed 300, up to rounding.

c)

Tremplin DEC receives 30 questionnaires under proportional allocation and 53 under Neyman, nearly double. Proportional logic looks only at the WEIGHT of the stratum: small stratum, small size. Neyman logic looks at the weight AND the SPREAD: a very heterogeneous stratum, here s=9s=9 hours against 4 elsewhere, needs more observations to be estimated with the same precision, otherwise it degrades the overall estimate. In other words, we invest the questionnaires where the uncertainty is greatest, exactly as we devote more revision time to the chapter we master least.

d)

We need n=1.962×0.250.082=0.96040.0064≈150n=\dfrac{1.96^{2}\times 0.25}{0.08^{2}}=\dfrac{0.9604}{0.0064}\approx 150 respondents in Tremplin DEC alone, and the finite population correction on Nh=620N_{h}=620 brings this number down to 1501+149620≈121\dfrac{150}{1+\dfrac{149}{620}}\approx 121. Neither of the previous allocations is enough: we then move to what is called an optimal allocation under constraint, first fixing the 121 for Tremplin and then splitting the remaining 179 between the other two sectors. The stratum is from then on OVERREPRESENTED relative to its real weight, and the respondents will have to be weighted at the analysis stage to recover a correct overall picture.

e)

Because the two objectives ask for opposite things. Estimating the CEGEP as a whole with the least possible error pushes toward allocating by weight and spread, so toward giving few questionnaires to small strata, whose contribution to the overall mean is small. COMPARING the sectors demands on the contrary a sufficient size IN EACH one, including the smallest, since the precision of a comparison is governed by the smaller of the two groups. A survey that pursues both objectives must therefore rank them explicitly, then restore the weights at the analysis stage: that is the role of sampling weights.

180141pre-university90106technical3053Tremplin DECproportionalNeyman

Part B: problems and reasoning (/50)

Exercise 6: Writing the questions: four faults that distort everything

A poorly written questionnaire produces flawless numbers on false answers, and no later analysis will rescue them. Four faults are enough to ruin an instrument.

  • a) “Do you find that the CEGEP is well located and well equipped? Yes / No”. Name the fault and rewrite.
  • b) “Don't you think it would be reasonable to raise fees in order to improve student services?”. Identify two distinct problems and rewrite.
  • c) “How many hours a week do you study? 0 to 5 / 5 to 10 / 10 to 15 / more than 20”. Identify two defects in the response categories and fix them.
  • d) A questionnaire first asks “Have you ever thought about dropping out?”, then “How would you rate your overall satisfaction?”. What effect should we fear and how do we remedy it?
  • e) “Have you ever cheated on an exam? Yes / No”. Which bias dominates, and which techniques can reduce it?

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  • a) Double-barrelled: two separate questions, one on location and one on equipment
  • b) Question both leading AND loaded; “Would you be in favour of or opposed to a fee increase of 60 dollars per term?”
  • c) Categories neither exclusive (5 belongs to two classes) nor exhaustive (15 to 20 is missing): bounds “to under” and “20 and over”
  • d) An order effect: general before specific, blocks separated, and above all rotation of the order between respondents
  • e) Social desirability; real anonymity, normalizing wording, randomized response (p=0.24p=0.24 here)
a)

This is a DOUBLE-BARRELLED question: it asks two, one about the location and one about the equipment. A respondent who finds the CEGEP well located but poorly equipped can answer neither yes nor no, and the analyst will never know which of the two the “yes” refers to. Rewrite: two separate questions, “Is the CEGEP well located?” and “Is the CEGEP's equipment adequate?”, each on a scale of four or five levels. The general rule can be spotted by ear: as soon as an “and” or an “or” links two objects of evaluation, you have to split.

b)

First problem, the question is LEADING: “don't you think” and “reasonable” suggest the expected answer, and some respondents follow the suggestion out of politeness. Second problem, it is LOADED: it ties the fee increase to an improvement presented as certain, which makes it impossible to oppose the increase without appearing to oppose the services. Neutral rewrite: “Would you be in favour of or opposed to a fee increase of 60 dollars per term?”, with a symmetric scale from in favour to opposed and a “don't know” option. The stated amount usefully replaces the adjective, which does not carry the same value for everyone.

c)

First defect, the categories are not MUTUALLY EXCLUSIVE: a student who studies exactly 5 hours can tick two boxes, and the total of the percentages no longer means anything. Second defect, they are not EXHAUSTIVE: nobody can answer for 15 to 20 hours, an interval that is simply absent. Fix: “0 to under 5”, “5 to under 10”, “10 to under 15”, “15 to under 20”, “20 and over”. The bounds now do not overlap and cover the whole possible range, zero included.

d)

We should fear an ORDER EFFECT, or contamination effect: the first question activates the memory of difficulties and lowers the satisfaction reported right after. We remedy it in three ways: place the general questions BEFORE the specific ones, separate the two blocks with unrelated questions, and above all rotate the order of the blocks from one respondent to the next, which an online questionnaire allows at no cost. Rotation does not remove the effect, it makes it measurable by spreading it evenly.

e)

This is SOCIAL DESIRABILITY bias: admitting to cheating costs something, even anonymously, and the proportion reported will underestimate reality. Three techniques reduce it. Real and visible anonymity, with a self-administered mode rather than an interview. Wording that normalizes, of the type “Many students sometimes... have you ever...”. And the RANDOMIZED RESPONSE technique: the respondent secretly flips a coin and answers the sensitive question only if it lands on heads, otherwise answers yes automatically; since the proportion of tails is known, we recover the proportion we are after by calculation without ever knowing what a given person answered.

Exercise 7: Nonresponse: the rate, the bias and what weighting does not do

A survey is judged not by its number of respondents but by what the absentees would have answered. The response rate is an indicator of risk, not a measure of bias.

Of 1,200 students contacted, 420 respond. A personal follow-up of 80 randomly chosen nonrespondents then makes it possible to measure their satisfaction.

62%38%420respondents80followed up
  • a) Compute the response rate and say what it allows you to conclude on its own.
  • b) The respondents report 62% satisfaction, the 80 nonrespondents followed up report 38%. Estimate the satisfaction of all 1,200 students contacted.
  • c) By how much does the naive estimate based on the respondents alone err? Write the general formula for nonresponse bias.
  • d) The response rate rises to 70% after a general follow-up, with no change in the gap between respondents and nonrespondents. Is the bias reduced, and by what proportion?
  • e) Weighting by age and by program is applied. Does it correct the bias measured here? Under what condition would it?

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  • a) 4201200=35%\dfrac{420}{1200}=35\%; on its own it measures the RISK, never the error
  • b) 0.35×0.62+0.65×0.38=0.4640.35\times 0.62+0.65\times 0.38=0.464, that is 46.4%46.4\%
  • c) 15.615.6 points of overestimate; bias=(1−t)(y‾r−y‾nr)\text{bias}=(1-t)(\overline{y}_{r}-\overline{y}_{nr})
  • d) Yes: 0.30×0.24=0.0720.30\times 0.24=0.072, that is 7.27.2 points, 46%46\% of the initial bias
  • e) No, except by coincidence: it would correct only if nonresponse depended solely on age and program
a)

Response rate: 4201200=0.35\dfrac{420}{1200}=0.35, that is 35%. On its own, it does not allow you to conclude to ANY bias: it measures the risk, not the error. A rate of 35% is perfectly harmless if the 780 absentees think like the 420 present, and catastrophic if they differ from them. What the rate announces is the size of the lever: the lower it is, the smaller the difference between respondents and nonrespondents needed to shift the result.

b)

The sample of 80 followed up estimates the nonrespondents at 38% satisfaction. The overall proportion is obtained by a weighted mean: 0.35×0.62+0.65×0.38=0.217+0.247=0.4640.35\times 0.62+0.65\times 0.38=0.217+0.247=0.464, that is about 46.4%. Note that the weight of 0.65 given to the nonrespondents nearly crushes the respondents' result: when two thirds of the sample is missing, they are the ones who decide.

c)

The naive estimate announces 62% against 46.4% in reality, an overestimate of 15.6 points. The general formula is bias=(1−t)(y‾r−y‾nr)\text{bias}=\left(1-t\right)\left(\overline{y}_{r}-\overline{y}_{nr}\right), where tt is the response rate: here 0.65×(0.62−0.38)=0.65×0.24=0.1560.65\times \left(0.62-0.38\right)=0.65\times 0.24=0.156. The formula says it all: the bias is the product of the missing share and the gap between the two groups, and it vanishes if either factor vanishes. That is why a survey with a 95% response rate is robust even if the absentees differ a lot, and a survey with 20% never is.

d)

Yes, and exactly in the ratio of the missing shares: the bias becomes 0.30×0.24=0.0720.30\times 0.24=0.072, that is 7.2 points instead of 15.6. The reduction is 0.0720.156≈0.46\dfrac{0.072}{0.156}\approx 0.46, so more than half of the bias has disappeared, only because the missing share went from 65% to 30%. Following up is thus the only action that acts directly on the bias, whereas sending out more initial invitations without improving the rate would change nothing at all.

e)

It does not correct it, except by coincidence. Weighting by age and program restores the STRUCTURE of the sample; it would correct the bias only if nonresponse depended solely on age and program, that is, if, at a given age and program, respondents and nonrespondents had the same satisfaction. But dissatisfaction is very probably a direct CAUSE of nonresponse, and disengagement is not a variable in the administrative file. Weighting would thus treat an observable symptom while leaving the cause intact. The only serious correction is the one this exercise made: go and measure a random subsample of nonrespondents, then recombine the two parts.

62%38%35%65% absentoverall 46.4%naive 62%

Exercise 8: Five claims to correct

Each of the following five claims is FALSE. Say why and give the correct statement.

  • 1) “A sample of 1,000 people is enough for Quebec but would be very insufficient for Canada, whose population is four times larger.”
  • 2) “Our survey has a response rate of 78%, so it is representative.”
  • 3) “Quota sampling is a form of stratification, so it makes it possible to compute a margin of error.”
  • 4) “We surveyed 336 students spread over 12 classes: the margin of error is that of a sample of 336.”
  • 5) “To avoid influencing respondents, it is better to offer no response categories and let everyone express themselves freely.”

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  • 1) FALSE: the margin is about 3.13.1 points for n=1,000n=1{,}000, in Quebec as in Canada
  • 2) FALSE: 78%78\% makes bias unlikely (1−t=0.221-t=0.22), it does not measure it
  • 3) FALSE: quotas impose the composition without a random draw, so no computable margin of error
  • 4) FALSE: with a design effect of 1.91.9, the effective size is 177177 and the margin 7.47.4 points, not 5.35.3
  • 5) FALSE: the open format shifts the influence, favours the more educated and makes the response rate drop
1)

FALSE. The margin of error depends on nn, and on NN only through the finite population correction, which is negligible as soon as the sample represents less than 5% of the population. With 1,000 people, the margin is about 3.1 points in Quebec, in Canada and in the United States alike. Correct statement: the precision of a poll depends on the number of people surveyed, not on the proportion of the population they represent, as long as that proportion remains small.

2)

FALSE, or more exactly not demonstrated. A rate of 78% is excellent and strongly reduces the risk, since nonresponse bias is written (1−t)(y‾r−y‾nr)\left(1-t\right)\left(\overline{y}_{r}-\overline{y}_{nr}\right) and the first factor is now only 0.22. But representativeness cannot be deduced from any rate: it is checked by comparing the sample with what we know of the population, and above all by going to measure a subsample of nonrespondents. Correct statement: a rate of 78% makes nonresponse bias unlikely and small; it does not measure it.

3)

FALSE. Quotas impose the COMPOSITION of the sample, stratification imposes the composition AND draws at random inside each group. It is the random draw, and it alone, that provides the inclusion probabilities without which no margin of error is defined. Correct statement: quota sampling is NONPROBABILITY sampling; it produces a sample of conforming structure, with no computable margin of error.

4)

FALSE. Students of the same class resemble one another, so each brings less new information than a student drawn on their own: that is the design effect. With a design effect of 1.9, the effective size falls to about 177, and the margin of error is that of 177, not of 336. Correct statement: the size must be divided by the design effect before any margin calculation, otherwise we announce a precision of about 5.3 points where the survey offers only 7.4.

5)

FALSE. Open questions have their uses, in exploration or at the end of a questionnaire, but they do not remove influence: they shift it toward whatever the respondent has in mind at the moment, they favour the more educated, they make the response rate drop and they force a coding after the fact that reintroduces the researcher's categories, this time without anyone being able to criticize them. Correct statement: we build response categories that are exhaustive, mutually exclusive and balanced, with an “other, please specify” option and a “don't know” option, and we reserve the open format for the small number of questions that really require it.

Exercise 9: Problem: designing the student life survey

The CEGEP, with 6,200 students, wants a survey on student life: balancing work and studies, sense of belonging, use of services. Budget: about 400 usable questionnaires. Every decision of the chapter meets here.

  • a) Choose a sampling frame and name its residual coverage defect.
  • b) Choose and justify a sampling plan, giving the strata selected.
  • c) The expected response rate is 32%. How many invitations must be sent to hope for 400 responses? What overall margin of error is obtained?
  • d) You want to compare students who work more than 20 hours a week, about 18% of the population, with the others. Check whether the planned sample allows this with a margin of 8 points on this subgroup.
  • e) Write the three lines of the technical note that the final report must carry.

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  • a) The registrar's file; residual defect, overcoverage of the dropouts, who are also hard to reach
  • b) Proportional stratified, strata sector crossed with study status: variables known for the whole frame and related to the themes
  • c) 4000.32=1,250\dfrac{400}{0.32}=1{,}250 invitations; margin 4.94.9 points, brought down to 4.74.7 by the correction
  • d) No: 7272 respondents give 11.611.6 points. We would need 150150, that is 833833 respondents in total
  • e) Frame and sizes, plan and response rate, overall margin and margin on subgroups
a)

The best frame available is the file of students registered in the current term, kept by the registrar's office: it is exhaustive, up to date, and it already carries age, program, sector and study status, which will serve as stratification and weighting variables. Residual defect: students who are registered but dropped out during the term are still listed, and those who have just arrived by transfer may be missing for a few weeks. Overcoverage is the more troublesome here, since dropouts are at once overrepresented in the frame and nearly unreachable, which will feed nonresponse.

b)

A STRATIFIED plan with proportional allocation, possibly adjusted for small strata. Strata selected: the sector, pre-university, technical and Tremplin, crossed with study status, full-time and part-time. Justification: these variables are known for the whole frame, they are strongly related to the three themes of the survey, and stratification guarantees that no sector will be accidentally absent. A cluster plan by class groups would be cheaper if we went into classrooms, but its design effect would waste half of the sample, which is pointless for an online survey where the marginal cost of one mailing is zero.

c)

We need 4000.32=1,250\dfrac{400}{0.32}=1{,}250 invitations. Overall margin with n=400n=400 and p=0.5p=0.5: E=1.960.25400=1.96×0.025=0.049E=1.96\sqrt{\dfrac{0.25}{400}}=1.96\times 0.025=0.049, that is 4.9 points, brought down to about 4.7 points by the finite population correction on 6,200. This is an honest precision for an overall picture. Note that the rate of 32% leaves 68% absent: the real risk of this survey is not its margin, it is its nonresponse, and the protocol must provide from the start for two follow-ups and a measurement on a subsample of nonrespondents.

d)

The subgroup represents 18% of the sample, about 0.18×400=720.18\times 400=72 respondents. The margin on this subgroup is 1.960.2572≈0.11551.96\sqrt{\dfrac{0.25}{72}}\approx 0.1155, that is 11.6 points: clearly beyond the 8 points aimed at. To reach 8 points, we would need 0.96040.0064≈150\dfrac{0.9604}{0.0064}\approx 150 respondents in this subgroup, so either raise the total sample to about 833 respondents, or deliberately oversample the heavy workers, which requires knowing their status before the mailing. Since this information is not in the registrar's file, the only practicable route is to increase the overall sample, or to accept a margin of 11.6 points on this subgroup and say so.

e)

“Survey conducted from March 3 to 21 among students registered for the winter term at the CEGEP; sampling frame: registrar's file, 6,200 registered students. Plan stratified by sector and study status, proportional allocation, 1,250 invitations, 402 usable questionnaires, response rate 32%. Data weighted by sector, status and age; overall margin of error of plus or minus 4.7 points, 19 times out of 20; margin raised to about 11.6 points for subgroups of about 70 respondents.” Three lines that give the frame, the plan and the precision, with its limits: this is exactly what a reader must find in order to judge the rest of the report.

Exercise 10: Problem: two polls, two results

In the same month, on the same question, two firms publish 54% and 41% in favour. Both announce a margin of 3 points. At least one of the two is wrong, and we have to be able to say which, or why both can be right.

54%41%firm Afirm B
  • a) Is the gap of 13 points compatible with two margins of 3 points? Reason on the intervals.
  • b) Firm A asked: “Are you in favour of the measure?”, firm B: “Are you in favour of the measure, even if it costs 400 million dollars?”. What do you conclude?
  • c) Firm A surveyed an online panel, firm B surveyed by telephone, cell phones included. How can the MODE shift a result by several points?
  • d) Firm A offered no “don't know” option, firm B offered one, chosen by 14% of respondents. Recompute B's result excluding the undecided and compare.
  • e) What should we demand from each firm to settle the matter, and what general principle follows?

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b)
c)
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e)
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  • a) No: [51.0,57.0][51.0, 57.0] and [38.0,44.0][38.0, 44.0] do not overlap, and the gap is worth more than six standard errors
  • b) The price cited by B makes support drop: A measures the principle, B the principle once the cost is known
  • c) Coverage, social desirability and the pace of reading the categories: three channels, several points each
  • d) 4186≈47.7%\dfrac{41}{86}\approx 47.7\%: the gap falls from 1313 to 6.36.3 points, with no opinion having changed
  • e) The exact wording, the order, the mode, the frame, the dates, the rate, the weighting and the fate of the undecided
a)

No, the gap is too large for chance alone. The intervals are [51.0,57.0]\left[51.0, 57.0\right] for A and [38.0,44.0]\left[38.0, 44.0\right] for B: they do not overlap, and seven points remain between them. More finely, the difference of two proportions from independent samples has a standard error of about 0.01532+0.01532≈0.0217\sqrt{0.0153^{2}+0.0153^{2}}\approx 0.0217, so a margin of about 4.2 points on the gap: a gap of 13 points is worth more than six standard errors. The conclusion is unavoidable: the difference does not come from sampling, it comes from the method.

b)

It probably explains most of the gap. B's question contains an additional piece of information, and a costly one: mentioning a price makes support drop for almost every measure, a phenomenon so consistent that sponsors use it deliberately. The two firms are therefore not measuring the same thing: A measures agreement with the principle, B measures agreement with the principle once the price is known. Both figures can be accurate at the same time, and it is the headline of the press release, if it speaks simply of “support for the measure”, that is wrong in both cases.

c)

The mode acts through three channels. COVERAGE: an online panel excludes the least connected, a telephone survey with cell phones reaches them better. SOCIAL DESIRABILITY: facing a human interviewer, a respondent softens their positions on sensitive subjects, whereas a self-administered questionnaire frees speech; the gap commonly reaches five points on questions of immigration or voting. Finally PACE and ATTENTION: online, the respondent sees all the categories, including the middle of the scale, whereas by telephone we mostly retain the first and the last read out. A serious firm therefore never compares two waves run in different modes without saying so.

d)

Out of 100 respondents of B, 41 are in favour, 14 undecided, so 45 opposed. Excluding the undecided, the share in favour becomes 4186≈0.477\dfrac{41}{86}\approx 0.477, that is 47.7%. The gap with A falls from 13 to about 6.3 points, a reduction by half. The treatment of the undecided is thus a third factor of discrepancy, purely conventional: forcing a choice distributes them between the two camps, offering the way out removes them from the denominator or leaves them in it, and each decision shifts the result by several points without a single opinion having changed.

e)

We must demand from each the EXACT wording of the question, the order of the preceding questions, the mode of collection, the sampling frame and the plan, the field dates, the response rate, the weighting variables and the treatment of the undecided. That is the content of a complete technical note, which professional codes require be published with any result made public. The general principle fits in one sentence: two polls can be compared only if everything, except what we want to compare, has been held constant. Failing that, the gap measures the method, not the opinion.

34384246505458A: [51, 57]B: [38, 44]7 points
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