Quantitative Methods in Social Science 360-300 • CEGEP, Montreal

Corrected exercises: index numbers, rates and constant dollars (360-300)

These ten corrected exercises, preceded by a list of calculations, cover the numbers you meet every day in a news release, in the Quantitative Methods course for Social Science, 360-300 at CEGEP: rate of change and percentage points, the multiplier and successive changes, the average annual rate, index numbers with base 100 and the change of base, current dollars and constant dollars, purchasing power, the unemployment rate and the employment rate, crude rates and standardized rates, doubling time and the rule of 70. These are the quantitative tools of applied economics, demography and sociology.

Exercise 0.1 opens the set with ten direct calculations, as in textbook drill lists: the percentage change of an increase and of a decrease, percentage points against percent, the final value and the initial value, the overall multiplier of two successive changes such as 1.25×0.841.25\times 0.84, the index with base 100 and the change of base, the conversion to constant dollars and the average annual rate. Each line has its value to find, checked as you type it.

By the end of the set, you can write a change correctly in points and in percent (exercise 1), chain changes and compute an average annual rate (exercise 2), compare two series through their index numbers (exercise 3), convert a salary into constant dollars and say whether purchasing power rose (exercise 4), compute an unemployment rate and see what discouragement does to it (exercise 5), standardize death rates on a reference population (exercise 6) and estimate a doubling time with the rule of 70 (exercise 7). The two problems follow twenty years of teacher salary in current and constant dollars (exercise 9) and reread an economic news release on inflation, disinflation and deflation (exercise 10).

The thread of the set fits in one sentence: a rate is a QUOTIENT, and everything depends on the choice of the denominator and of the base. Changing the base does not change reality, only the published number, which is why five exact figures can describe the same salary increase. Three pitfalls are named outright: percentage points mistaken for percentages (exercises 1 and 8), successive rates added instead of multiplied (exercises 2 and 8), and crude rates compared between populations with different age structures (exercises 6 and 8).

11 corrected exercises • 110 points • 150 minutes

This chapter is part of 360-300, every chapter with its set and sheet Before you start Revision sheet: the traps and the method for this chapter

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Course recap

  • • Change in POINTS: the difference of two percentages. Change in PERCENT: end−startstart\dfrac{\text{end}-\text{start}}{\text{start}}. Never mix the two.
  • • Successive rates MULTIPLY through their multipliers: +10%+10\% then −10%-10\% gives 1.10×0.90=0.991.10\times 0.90=0.99, so a decrease of 1%.
  • • To undo a decrease of tt, you need an increase of t1−t\dfrac{t}{1-t}, always larger than tt.
  • • Average annual rate over nn periods: t=(VfVi)1/n−1t=\left(\dfrac{V_{f}}{V_{i}}\right)^{1/n}-1. It is a geometric mean, never the total increase divided by nn.
  • • Index number with base 100: I=VVbase×100I=\dfrac{V}{V_{base}}\times 100. Two index numbers are compared by their QUOTIENT, never by their difference.
  • • Change of base: divide all the index numbers by the one of the new reference year, then multiply by 100. The ratios are unchanged.
  • • Constant dollars: Vconstant=Vcurrent×Itarget yearIyear of the amountV_{constant}=V_{current}\times \dfrac{I_{\text{target year}}}{I_{\text{year of the amount}}}.
  • • Purchasing power: multiplier of the salary divided by multiplier of prices. Any salary increase smaller than inflation is a real decrease.
  • • Unemployment rate =unemployedlabour force=\dfrac{\text{unemployed}}{\text{labour force}}; employment rate =employed personspopulation aged 15 and over=\dfrac{\text{employed persons}}{\text{population aged 15 and over}}. The second one is not affected by discouragement.
  • • Direct standardization: apply the actual SPECIFIC rates of each population to a COMMON reference structure. It removes the effect of the age structure.
  • • Rule of 70: doubling time ≈70rate in percent\approx \dfrac{70}{\text{rate in percent}}, because ln⁡2≈0.693\ln 2\approx 0.693 and ln⁡(1+t)≈t\ln(1+t)\approx t for small tt.
  • • Inflation: prices rise. DISINFLATION: they rise more slowly. DEFLATION: they fall, the rate is negative.

Calculations: the changes and index numbers to compute

Exercise 0.1: Computing changes, multipliers and index numbers: ten direct calculations

For each line, do the calculation asked for. A change is written in percent, to one decimal, with a minus sign for a decrease; an amount is written in dollars and an index number as it comes, to one decimal when it does not come out even.

One idea for all ten lines: every change is a MULTIPLIER. We write end=start×m\text{end}=\text{start}\times m, with m=1+tm=1+t for a change tt; a series of changes multiplies the multipliers; an index number with base 100 is a multiplier times 100100; and converting to constant dollars means multiplying by the ratio of the price indexes, the one of the target year over the one of the year of the amount.

  • a) The percentage change of a value that goes from 1,2501{,}250 to 1,4101{,}410.
  • b) The percentage change of a value that goes from 3,6003{,}600 to 3,3303{,}330.
  • c) A rate goes from 15.0%15.0\% to 18.6%18.6\%: the change in percentage points, then in percent.
  • d) The final value after an increase of 6.5%6.5\% applied to 2,8002{,}800 dollars.
  • e) The initial value of an amount that is worth 1,9801{,}980 dollars after a decrease of 12%12\%.
  • f) The overall multiplier of an increase of 25%25\% followed by a decrease of 16%16\%, then the overall percentage change.
  • g) The index number in 2024, base 100 in 2019, of a quantity worth 18,40018{,}400 in 2019 and 21,16021{,}160 in 2024.
  • h) An index number is 100100 in 2015, 112112 in 2020 and 140140 in 2024. With base 100 in 2020: its value in 2024, then in 2015.
  • i) A price index is 120120 in 2012 and 160160 in 2024. The value of 54,00054{,}000 dollars of 2024 in constant 2012 dollars.
  • j) The average annual rate of a quantity that goes from 5,0005{,}000 to 6,4006{,}400 in 44 years.

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  • a) 1601,250=0.128\frac{160}{1{,}250}=0.128; +12.8%+12.8\%
  • b) −2703,600=−0.075\frac{-270}{3{,}600}=-0.075; −7.5%-7.5\%
  • c) 3.63.6 points; +24.0%+24.0\%
  • d) 2,800×1.0652{,}800\times 1.065; 2,9822{,}982 dollars
  • e) 1,9800.88\frac{1{,}980}{0.88}; 2,2502{,}250 dollars
  • f) 1.25×0.84=1.051.25\times 0.84=1.05; +5.0%+5.0\%
  • g) 21,16018,400×100\frac{21{,}160}{18{,}400}\times 100; 115.0115.0
  • h) 140112×100=125.0\frac{140}{112}\times 100=125.0; 100112×100≈89.3\frac{100}{112}\times 100\approx 89.3
  • i) 54,000×12016054{,}000\times\frac{120}{160}; 40,50040{,}500 dollars of 2012
  • j) 1.2814−1≈0.06371.28^{\frac{1}{4}}-1\approx 0.0637; about 6.4%6.4\% per year

The move that decides everything: a change is ALWAYS measured against the starting value, and successive changes MULTIPLY through their multipliers. Almost every mistake on this list comes from a wrong denominator or from adding percentages.

a)

1,410−1,2501,250=1601,250=0.128\frac{1{,}410-1{,}250}{1{,}250}=\frac{160}{1{,}250}=0.128, an increase of 12.8%12.8\%.

b)

3,330−3,6003,600=−2703,600=−0.075\frac{3{,}330-3{,}600}{3{,}600}=\frac{-270}{3{,}600}=-0.075, a decrease of 7.5%7.5\%. Pitfall: dividing by the final value, 2703,330≈8.1%\frac{270}{3{,}330}\approx 8.1\%.

c)

In points: 18.6−15.0=3.618.6-15.0=3.6 percentage points. In percent: 3.615.0=0.24\frac{3.6}{15.0}=0.24, an increase of 24.0%24.0\%. Pitfall: announcing an increase "of 3.6%3.6\%", which confuses the difference of two rates with their relative change.

d)

The multiplier is 1.0651.065: 2,800×1.065=2,9822{,}800\times 1.065=2{,}982 dollars.

e)

A decrease of 12%12\% is the multiplier 0.880.88, so start=1,9800.88=2,250\text{start}=\frac{1{,}980}{0.88}=2{,}250 dollars. Pitfall: adding 12%12\% to the final value, 1,980×1.12≈2,2181{,}980\times 1.12\approx 2{,}218, which measures the decrease against the wrong value.

f)

1.25×0.84=1.051.25\times 0.84=1.05: the overall multiplier is 1.051.05, an increase of 5.0%5.0\%. Pitfall: adding the rates, 25−16=9%25-16=9\%.

g)

I=21,16018,400×100=1.15×100=115.0I=\frac{21{,}160}{18{,}400}\times 100=1.15\times 100=115.0: the quantity has increased by 15%15\% since 2019.

h)

Divide each index number by the one of 2020, then multiply by 100100. In 2024: 140112×100=125.0\frac{140}{112}\times 100=125.0. In 2015: 100112×100≈89.3\frac{100}{112}\times 100\approx 89.3. Pitfall: subtracting 1212 points from each index number, which gives 128128 and 8888 and does not preserve the ratios.

i)

54,000×120160=54,000×0.75=40,50054{,}000\times\frac{120}{160}=54{,}000\times 0.75=40{,}500 dollars of 2012. Pitfall: multiplying by 160120\frac{160}{120}, which gives 72,00072{,}000; since prices have risen, an amount expressed in dollars of the earlier year must be SMALLER.

j)

We look for tt such that 5,000×(1+t)4=6,4005{,}000\times(1+t)^{4}=6{,}400, so (1+t)4=1.28(1+t)^{4}=1.28 and 1+t=1.2814≈1.06371+t=1.28^{\frac{1}{4}}\approx 1.0637: about 6.4%6.4\% per year. Pitfall: dividing the total increase by 44, 284=7%\frac{28}{4}=7\%, which applied four times gives 1.074≈1.3111.07^{4}\approx 1.311 and not 1.281.28.

Check: every result goes back into its multiplier. In a), 1,250×1.128=1,4101{,}250\times 1.128=1{,}410; in e), 2,250×0.88=1,9802{,}250\times 0.88=1{,}980; in f), 100×1.25×0.84=105100\times 1.25\times 0.84=105; in j), 5,000×1.06374≈6,4005{,}000\times 1.0637^{4}\approx 6{,}400. A change of base keeps the ratios: 12589.3≈1.40\frac{125}{89.3}\approx 1.40, like 140100\frac{140}{100}.

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Part A: the basics (/50)

Exercise 1: Rate of change, percentage points and percent

The simplest calculation of the course is also the one that produces the most false sentences in the press: the change in a percentage is not a percentage.

  • a) The unemployment rate goes from 6.0% to 7.5%. Express the change in PERCENTAGE POINTS, then in PERCENT.
  • b) A party goes from 32% to 36% in voting intentions. Write the two corresponding correct sentences.
  • c) Enrolment goes from 850 to 782. Compute the relative change, then the change that would bring it back to 850.
  • d) Explain why the decrease and the catch-up increase do not have the same percentage.
  • e) A newspaper writes: "the poverty rate rose by 20%, from 10% to 12%". Is the sentence correct?

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  • a) 1.51.5 percentage points, or +25%+25\% in relative terms
  • b) "The party gains 44 POINTS" and "voting intentions rise by 12.5%12.5\%": both are exact
  • c) Decrease of 8.0%8.0\%; to get back to 850850, an increase of 8.7%8.7\% is needed
  • d) Because the denominator differs; undoing a decrease of tt requires an increase of t1−t\dfrac{t}{1-t}
  • e) Correct, which is what makes it tricky: +2+2 points AND +20%+20\%, both must be written
a)

In percentage POINTS: 7.5−6.0=1.57.5-6.0=1.5 points. In PERCENT: 7.5−6.06.0=0.25\dfrac{7.5-6.0}{6.0}=0.25, an increase of 25%. The two numbers, 1.5 and 25, describe the same event and are not interchangeable. The writing rule is simple: a difference of two percentages is said in POINTS; a ratio of two percentages is said in PERCENT.

b)

First sentence: "the party gains 4 POINTS, going from 32% to 36%". Second sentence: "voting intentions for the party rise by 12.5%, since 36−3232=0.125\dfrac{36-32}{32}=0.125". The first is the one political analysts use, because it compares directly with the margin of error, which is also expressed in points. The second is correct but misleading in this context: it suggests spectacular progress where four points may fit within the sampling noise.

c)

Relative change: 782−850850=−68850=−0.08\dfrac{782-850}{850}=\dfrac{-68}{850}=-0.08, a decrease of 8.0%. To get back to 850 from 782: 850−782782=68782≈0.0870\dfrac{850-782}{782}=\dfrac{68}{782}\approx 0.0870, an increase of 8.7%. So it takes a LARGER increase than the decrease suffered to get back to the starting point.

d)

Because a relative change is always computed on the STARTING value, and the two movements do not have the same starting value: 850 for the decrease, 782 for the increase. The same absolute gap of 68 divided by a smaller denominator gives a larger percentage. Formally, a decrease of tt followed by an increase of tt gives the factor (1−t)(1+t)=1−t2<1\left(1-t\right)\left(1+t\right)=1-t^{2}<1: you never return to the starting point. To undo a decrease of tt, you need an increase of t1−t\dfrac{t}{1-t}.

e)

It is correct, and that is precisely what makes it tricky. Going from 10% to 12% is indeed a relative increase of 12−1010=20%\dfrac{12-10}{10}=20\%, and it is also an increase of 2 POINTS. The wording chosen, though not false, is the one with the most impact, and the hurried reader will remember that a fifth of the population has fallen into poverty. A rigorous newspaper writes both: "the rate goes from 10% to 12%, two points higher, an increase of 20%".

Exercise 2: Successive changes do not add up

The second source of errors: chaining percentages. They are MULTIPLIED, as multipliers, and never added.

  • a) A price rises by 10% then falls by 10%. What is the overall change?
  • b) Tuition rises by 3% per year for 5 years. What is the total increase? And the gap with the naive addition of 15%?
  • c) A population shrinks by 2% per year for 12 years. What proportion remains?
  • d) A salary goes from 42,000 to 51,500 dollars in 7 years. Compute the AVERAGE annual growth rate.
  • e) A store advertises "30% off, plus an extra 20% at the register". Is the total discount 50%?

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  • a) 1.10×0.90=0.991.10\times 0.90=0.99: a decrease of 1%1\%
  • b) 1.035≈1.15931.03^{5}\approx 1.1593, so +15.93%+15.93\%; naive addition announces 15%15\%
  • c) 0.9812≈0.78470.98^{12}\approx 0.7847: 78.5%78.5\% remains, a loss of 21.5%21.5\% and not 24%24\%
  • d) (51,50042,000)1/7−1≈2.96%\left(\dfrac{51{,}500}{42{,}000}\right)^{1/7}-1\approx 2.96\% per year, geometric mean
  • e) No: 0.70×0.80=0.560.70\times 0.80=0.56, so a 44%44\% discount and not 50%50\%
a)

Multipliers: 1.101.10 then 0.900.90, so 1.10×0.90=0.991.10\times 0.90=0.99. The price has therefore FALLEN by 1%. An item at 200 dollars goes to 220, then to 198. The order of the two changes makes no difference, since multiplication is commutative: a good argument to convince a student that the result does not depend on the direction of reading.

b)

Overall multiplier: 1.035≈1.15931.03^{5}\approx 1.1593, an increase of 15.93%. The naive addition would give 15%, which underestimates by nearly a full point. The gap comes from COMPOUND INTEREST: the increase of the third year applies to an amount that has already risen twice. The gap grows quickly with the number of periods: over 20 years, 1.0320≈1.8061.03^{20}\approx 1.806 against 1.60 for the addition, a difference of 20 points.

c)

Multiplier: 0.9812≈0.78470.98^{12}\approx 0.7847. About 78.5% of the population therefore remains, a loss of 21.5% in twelve years, whereas naive addition would announce 24%. Here the naive error EXAGGERATES the loss, because each decrease applies to a population that is already reduced. Remember the rule: compounding softens decreases and amplifies increases compared with addition.

d)

We look for tt such that 42,000×(1+t)7=51,50042{,}000\times \left(1+t\right)^{7}=51{,}500, so (1+t)7=51,50042,000≈1.22619\left(1+t\right)^{7}=\dfrac{51{,}500}{42{,}000}\approx 1.22619 and 1+t=1.226191/7≈1.029581+t=1.22619^{1/7}\approx 1.02958. The average annual rate is therefore about 2.96%. It is a GEOMETRIC mean and not an arithmetic one: dividing the total increase of 22.6% by 7 would give 3.23%, a number that does not rebuild the final result if you apply it seven times.

e)

No. The two discounts apply in succession: 0.70×0.80=0.560.70\times 0.80=0.56, so the customer pays 56% of the price and the total discount is 44%, not 50%. On a 100-dollar item: 70 dollars after the first discount, then 56 dollars after the second. The gap of six points is exactly the product 0.30×0.20=0.060.30\times 0.20=0.06, that is, the discount that would be counted twice if you added. It is the commercial version of the same pitfall, and it is perfectly legal because the ad never says that the discounts add up.

Exercise 3: Index numbers with base 100: comparing what has no common unit

An index number brings every series back to a common starting point, conventionally 100. It then becomes possible to compare a rent in dollars and an income in dollars, or even a number of enrolments and a surface area.

  • a) Average rent goes from 780 to 1,186 dollars in six years. Compute the index number of the last year, base 100 the first year.
  • b) Median income goes from 34,200 to 40,000 dollars over the same period. Compute its index number and compare the two trends.
  • c) By how much has rent risen RELATIVE to income? Give the ratio of the two index numbers and interpret it.
  • d) We want to change the base and take year 3 as the reference. The rent index was 129 there. Recompute the index numbers of years 0 and 5 in the new base.
  • e) Can an index number fall below 100? What does the value 87 mean then?

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  • a) 1,186780×100≈152.1\dfrac{1{,}186}{780}\times 100\approx 152.1, so +52%+52\%
  • b) 40,00034,200×100≈117.0\dfrac{40{,}000}{34{,}200}\times 100\approx 117.0, so +17%+17\%
  • c) 152.1117.0≈1.300\dfrac{152.1}{117.0}\approx 1.300: rent rises 30%30\% faster than income
  • d) Year 0: 77.577.5. Year 5: 117.9117.9. The ratio 1.5211.521 is unchanged
  • e) Yes: 8787 means 87%87\% of the reference value, a decrease of 13%13\%
a)

I=1,186780×100≈152.1I=\dfrac{1{,}186}{780}\times 100\approx 152.1. Rent has therefore risen by about 52% in six years. An index number reads directly as a percentage of the base year, which is its whole point: 152 means "152% of what it was", so 52% more.

b)

I=40,00034,200×100≈117.0I=\dfrac{40{,}000}{34{,}200}\times 100\approx 117.0, an increase of 17%. Both series start at 100 and end at 152 and 117: on the graph, the gap widens steadily, which no comparison of raw dollars would have shown, since 1,186 dollars and 40,000 dollars cannot be compared.

c)

Ratio of the index numbers: 152.1117.0≈1.300\dfrac{152.1}{117.0}\approx 1.300. Rent has therefore risen 30% faster than income. In other words, the share of income spent on rent has been multiplied by 1.30: if it was 27% at the start, it is now about 35%. It is this quotient of index numbers, and not the difference 152 minus 117, that has a meaning: subtracting two index numbers would give 35 "index points", a quantity whose interpretation depends on the base chosen.

d)

Changing the base means dividing all the index numbers by the one of the new reference year and multiplying by 100. Year 0: 100129×100≈77.5\dfrac{100}{129}\times 100\approx 77.5. Year 5: 152.1129×100≈117.9\dfrac{152.1}{129}\times 100\approx 117.9. We check that year 3 is now exactly 100. The TREND is unchanged: the ratio of year 5 to year 0 is 117.977.5≈1.521\dfrac{117.9}{77.5}\approx 1.521 in the new base as in the old one. An index number therefore contains no absolute information, only ratios.

e)

Yes, as soon as the value is below that of the base year. An index number of 87 means that the quantity is now worth only 87% of its reference value, a decrease of 13%. This is a common reading for indexes of industrial production or school enrolment. Be careful not to say "the index fell by 13 points" if the base is not 100: the correct wording always compares to the base explicitly named, for example "87, base 100 in 2015".

12345690100110120130140150160rent: 152.1income: 117.0yearindex

Exercise 4: Current dollars, constant dollars and purchasing power

An amount in 2005 dollars and an amount in 2025 dollars are not in the same unit: you have to convert before comparing. The consumer price index is the exchange rate between the two.

Take a price index equal to 100 in 2005, 120.0 in 2015 and 150.0 in 2025.

  • a) A salary of 48,000 dollars in 2005 and of 68,000 dollars in 2025: convert the second one into constant 2005 dollars.
  • b) Has purchasing power risen or fallen? By how much, in percent?
  • c) What 2025 salary would have been needed to maintain exactly the purchasing power of 2005?
  • d) The AVERAGE ANNUAL inflation rate over these twenty years: compute it.
  • e) A friend claims: "my salary has risen by 42% in twenty years, I earn far more than before". What do you answer in one sentence and one calculation?

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  • a) 68,000×100150≈45,33368{,}000\times \dfrac{100}{150}\approx 45{,}333 dollars of 2005
  • b) It has FALLEN by about 5.6%5.6\%
  • c) 48,000×1.50=72,00048{,}000\times 1.50=72{,}000 dollars, that is 4,0004{,}000 more than the 68,00068{,}000 paid
  • d) 1.51/20−1≈2.05%1.5^{1/20}-1\approx 2.05\% per year
  • e) "Prices rose by 50%50\%": 1.41671.50≈0.944\dfrac{1.4167}{1.50}\approx 0.944, you are 5.6%5.6\% poorer
a)

Conversion: 68,000×100150=68,000×0.6667≈45,33368{,}000\times \dfrac{100}{150}=68{,}000\times 0.6667\approx 45{,}333 dollars of 2005. The rule is to multiply by the ratio "index of the TARGET year over index of the year of the amount". You can check the direction of the calculation with common sense: since prices have risen, a 2025 dollar is worth less, so the converted amount must be SMALLER than 68,000.

b)

Purchasing power has FALLEN: 45,333 dollars of 2005 against 48,000 in 2005, a decrease of 45,333−48,00048,000≈−0.0556\dfrac{45{,}333-48{,}000}{48{,}000}\approx -0.0556, about 5.6%. This is the central result of the chapter: a salary that rises by 42% in twenty years can mean impoverishment, because prices rose by 50%.

c)

You would have needed 48,000×150100=72,00048{,}000\times \dfrac{150}{100}=72{,}000 dollars in 2025. The gap with the 68,000 actually paid, that is 4,000 dollars, measures exactly the loss of purchasing power in 2025 dollars. We can check consistency: 68,00072,000≈0.944\dfrac{68{,}000}{72{,}000}\approx 0.944, which indeed gives back the decrease of 5.6% from the previous question.

d)

We look for tt such that (1+t)20=150100=1.5\left(1+t\right)^{20}=\dfrac{150}{100}=1.5, so 1+t=1.51/20≈1.020481+t=1.5^{1/20}\approx 1.02048 and t≈2.05%t\approx 2.05\% per year. An annual inflation rate of 2%, which looks harmless, is therefore enough to cost a nominal amount a third of its purchasing power in twenty years, since 11.5≈0.667\dfrac{1}{1.5}\approx 0.667.

e)

"Your salary rose by 42%, prices by 50%: you are 5.6% poorer." The calculation fits on one line: 1.41671.50≈0.944\dfrac{1.4167}{1.50}\approx 0.944, starting from the exact multiplier of the salary, 68,00048,000=1.4167\dfrac{68{,}000}{48{,}000}=1.4167, and not from its rounding to 1.421.42. This is the general formula for purchasing power, multiplier of the salary divided by multiplier of prices, and it is the only calculation to keep from this exercise. Any salary whose increase is smaller than inflation represents a real decrease, whatever the headline figure.

2005201020152020202540444852566064687268,000 current45,333 (2005 dollars)yearthousands of dollars

Exercise 5: The unemployment rate: what the denominator decides

A rate is a quotient, and what matters is the denominator. The unemployment rate is the most disputed example, because the choice of who counts as unemployed changes the result by several points.

384,000 employed32,000 unemployedinactive640,000 aged 15 and over
  • a) A region has 640,000 people aged 15 and over, of whom 384,000 are employed and 32,000 are actively looking for work. Compute the unemployment rate and the participation rate.
  • b) 18,000 people have stopped looking for work, discouraged. Recompute the unemployment rate counting them as unemployed.
  • c) The number of jobs stays the same but 12,000 unemployed people leave the labour market. What happens to the unemployment rate?
  • d) Explain why a drop in the unemployment rate is not necessarily good news.
  • e) The employment rate is the ratio of employed persons to the population aged 15 and over. Compute it and say how it complements the unemployment rate.

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  • a) Labour force 416,000416{,}000; unemployment 7.7%7.7\%; participation 65%65\%
  • b) 50,000434,000≈11.5%\dfrac{50{,}000}{434{,}000}\approx 11.5\%, nearly four points more for the same reality
  • c) 20,000404,000≈5.0%\dfrac{20{,}000}{404{,}000}\approx 5.0\%: 2.72.7 points lower without a single job created
  • d) Because the rate also falls when the denominator shrinks, that is, through discouragement
  • e) 384,000640,000=60%\dfrac{384{,}000}{640{,}000}=60\%; its denominator is not affected by job-search behaviour
a)

The LABOUR FORCE is 384,000+32,000=416,000384{,}000+32{,}000=416{,}000 people, those who have a job or are actively looking for one. Unemployment rate: 32,000416,000≈0.0769\dfrac{32{,}000}{416{,}000}\approx 0.0769, that is 7.7%. Participation rate: 416,000640,000=0.65\dfrac{416{,}000}{640{,}000}=0.65, that is 65%. The denominator of the unemployment rate deserves emphasis: it is not the total population, it is the labour force, which excludes full-time students, retirees and people who are not looking.

b)

Counting the 18,000 discouraged people as unemployed, the labour force becomes 416,000+18,000=434,000416{,}000+18{,}000=434{,}000 and the number of unemployed 32,000+18,000=50,00032{,}000+18{,}000=50{,}000. The rate becomes 50,000434,000≈0.1152\dfrac{50{,}000}{434{,}000}\approx 0.1152, that is 11.5%. A gap of nearly four points for one and the same economic reality, only because the definition of "looking for work" was changed. This is why Statistics Canada publishes several complementary rates, R1 to R8, rather than a single one.

c)

The labour force falls to 416,000−12,000=404,000416{,}000-12{,}000=404{,}000 and the unemployed to 20,00020{,}000. The rate becomes 20,000404,000≈0.0495\dfrac{20{,}000}{404{,}000}\approx 0.0495, that is 5.0% instead of 7.7%. The rate has therefore DROPPED by 2.7 points although no job has been created: people simply stopped looking. This is the exact mechanism of discouragement, and it operates strongly at the end of a recession.

d)

Because the rate can fall for two opposite reasons: because the numerator falls, unemployed people find a job, which is good news; or because the denominator falls, unemployed people leave the labour force, which is bad news. Both movements give the same change in the rate. To decide, you have to look at the EMPLOYMENT RATE and the participation rate: if the unemployment rate falls and the employment rate falls too, it is discouragement.

e)

Employment rate: 384,000640,000=0.60\dfrac{384{,}000}{640{,}000}=0.60, that is 60%. It complements the unemployment rate because its denominator, the total population aged 15 and over, does not depend on job-search behaviour: it is NOT AFFECTED by discouragement. When unemployed people withdraw, the unemployment rate falls and the employment rate stays the same, which immediately reveals the unintended trick. Publishing both together is the correct practice, and it is what statistical agencies do.

384,000 employed32,000 unemployedinactive640,000 aged 15 and overlabour force 416,000: unemployment 7.7%aged 15 and over 640,000: employment 60%

Part B: problems and reasoning (/50)

Exercise 6: Crude rates, specific rates and standardized rates

Comparing two populations by a crude rate often amounts to comparing their age structures rather than the phenomenon under study. Direct standardization corrects exactly that, and it is the basic tool of demography and epidemiology.

Two regions, with their death rates per 1,000 inhabitants by age group.

Age groupRegion A: shareA: rateRegion B: shareB: rate
Under 4060%1.040%1.2
40 to 6430%6.030%7.0
65 and over10%50.030%55.0
  • a) Compute the CRUDE death rate of each region.
  • b) Compare the SPECIFIC rates by age group. Which region is deadlier at equal age?
  • c) Standardize the two rates on a reference population split 50%, 30% and 20%.
  • d) Compare the crude gap and the standardized gap. What did standardization do?
  • e) A mayor of region A declares: "our population is healthier, our death rate is three times lower". Correct this.

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  • a) 7.47.4 per 1,0001{,}000 in A, 19.0819.08 in B
  • b) B, but only slightly: ratios 1.201.20, 1.171.17 and 1.101.10 by bracket, against 2.582.58 crude
  • c) 12.312.3 for A, 13.713.7 for B
  • d) Crude gap 11.6811.68 against standardized gap 1.41.4: more than 88%88\% of the gap came from age
  • e) "Our population is younger"; at comparable structure, 12.312.3 against 13.713.7, that is 10%10\% lower
a)

Crude rate of A: 0.60×1.0+0.30×6.0+0.10×50.0=0.6+1.8+5.0=7.40.60\times 1.0+0.30\times 6.0+0.10\times 50.0=0.6+1.8+5.0=7.4 per 1,000. Crude rate of B: 0.40×1.2+0.30×7.0+0.30×55.0=0.48+2.1+16.5=19.080.40\times 1.2+0.30\times 7.0+0.30\times 55.0=0.48+2.1+16.5=19.08 per 1,000. Region B therefore shows a crude rate two and a half times higher.

b)

At equal age, region B is indeed the deadlier, but only slightly: 1.2 against 1.0 among those under 40, 7.0 against 6.0 among the 40 to 64, 55.0 against 50.0 among seniors. The ratios are 1.20, 1.17 and 1.10 respectively, an excess mortality of about 10 to 20% in each bracket, nowhere near the ratio of 2.58 between the crude rates.

c)

Standardized rate of A: 0.50×1.0+0.30×6.0+0.20×50.0=0.5+1.8+10.0=12.30.50\times 1.0+0.30\times 6.0+0.20\times 50.0=0.5+1.8+10.0=12.3. Standardized rate of B: 0.50×1.2+0.30×7.0+0.20×55.0=0.6+2.1+11.0=13.70.50\times 1.2+0.30\times 7.0+0.20\times 55.0=0.6+2.1+11.0=13.7. We apply the ACTUAL specific rates of each region to a COMMON, fictitious age structure: the two numbers obtained describe what would happen if the two regions had the same age pyramid.

d)

Crude gap: 19.08−7.4=11.6819.08-7.4=11.68 per 1,000, with a ratio of 2.58. Standardized gap: 13.7−12.3=1.413.7-12.3=1.4, with a ratio of 1.11. Standardization removed the effect of the AGE STRUCTURE: it shows that more than 88% of the crude gap came from the fact that region B has three times as many seniors, and not from a difference in mortality at equal age. This is the typical result of this tool, and it almost always overturns the naive interpretation.

e)

The mayor is comparing crude rates, so mainly age pyramids. Correction: "our population is younger, which explains most of our lower crude rate. With a comparable age structure, our mortality is 12.3 per 1,000 against 13.7 for our neighbour, about 10% lower, which remains a real advantage but a much more modest one." It should be added that this residual advantage itself needs an explanation, income, access to care, environment, and that a standardized rate is never more than a starting point for analysis.

7.419.08ABcrude12.313.7ABstandardized

Exercise 7: Growth, doubling time and the rule of 70

Growth at a constant rate is EXPONENTIAL growth, and human intuition is very poor at it. The rule of 70 is the shortcut that makes it readable.

  • a) A population grows by 2.0% per year. Compute its exact doubling time, then with the rule of 70.
  • b) Justify the rule of 70 from ln⁡(2)\ln(2).
  • c) A city of 180,000 inhabitants grows by 1.4% per year. What will its population be in 25 years?
  • d) Two countries, one at 0.5% and the other at 3.0% per year. After how many years will the second have tripled, and where will the first be?
  • e) A columnist writes that "3% growth is modest". What is the reply in one sentence with numbers?

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  • a) ln⁡2ln⁡1.02≈35.0\dfrac{\ln 2}{\ln 1.02}\approx 35.0 years, and 702=35\dfrac{70}{2}=35
  • b) nln⁡(1+t)=ln⁡2≈0.693n\ln(1+t)=\ln 2\approx 0.693 and ln⁡(1+t)≈t\ln(1+t)\approx t, hence n≈69.3pn\approx \dfrac{69.3}{p}, rounded to 70
  • c) 180,000×1.01425≈254,800180{,}000\times 1.014^{25}\approx 254{,}800 inhabitants; doubling in 5050 years, so ×2\times \sqrt{2} in 25
  • d) ln⁡3ln⁡1.03≈37.2\dfrac{\ln 3}{\ln 1.03}\approx 37.2 years; the other is only at 1.2041.204, a final ratio of 2.52.5
  • e) "At 3%3\%, everything doubles in 2323 years and is multiplied by 88 in 7070 years"
a)

Exact: we solve (1.02)n=2\left(1.02\right)^{n}=2, so n=ln⁡2ln⁡1.02=0.69310.019803≈35.0n=\dfrac{\ln 2}{\ln 1.02}=\dfrac{0.6931}{0.019803}\approx 35.0 years. Rule of 70: 702.0=35\dfrac{70}{2.0}=35 years. The agreement is excellent, and it stays so for all the usual rates, say from 0.5% to 10%.

b)

Doubling requires (1+t)n=2\left(1+t\right)^{n}=2, so nln⁡(1+t)=ln⁡2≈0.693n\ln\left(1+t\right)=\ln 2\approx 0.693. For small tt, ln⁡(1+t)≈t\ln\left(1+t\right)\approx t, hence n≈0.693tn\approx \dfrac{0.693}{t}. Expressing the rate as a PERCENTAGE, t=p100t=\dfrac{p}{100}, we get n≈69.3pn\approx \dfrac{69.3}{p}, rounded to 70 because that number has many whole divisors, which makes mental arithmetic easy: 70 divided by 2, by 5, by 7 or by 10 comes out even.

c)

180,000×(1.014)25=180,000×1.4159≈254,800180{,}000\times \left(1.014\right)^{25}=180{,}000\times 1.4159\approx 254{,}800 inhabitants. You can check with the rule of 70: the doubling time is 701.4=50\dfrac{70}{1.4}=50 years, so in 25 years, half a period, the population should be multiplied by about 2≈1.414\sqrt{2}\approx 1.414, which agrees with the exact calculation to within two thousandths.

d)

Tripling at 3%: n=ln⁡3ln⁡1.03=1.09860.029559≈37.2n=\dfrac{\ln 3}{\ln 1.03}=\dfrac{1.0986}{0.029559}\approx 37.2 years. Meanwhile, the country at 0.5% is multiplied by (1.005)37.2≈1.204\left(1.005\right)^{37.2}\approx 1.204, an increase of 20%. In under forty years, a gap of 2.5 points in the annual rate therefore produces a ratio of 31.204≈2.5\dfrac{3}{1.204}\approx 2.5 between the two countries. It is this mechanism, and not any particular event, that explains the divergence of demographic and economic trajectories over half a century.

e)

"At 3% per year, everything doubles in 23 years and is multiplied by 8 in 70 years." The calculation: 703≈23.3\dfrac{70}{3}\approx 23.3 years per doubling, and 70 years contain three doublings, hence a factor 23=82^{3}=8. This sentence is enough to make clear that no constant growth rate is modest over a long period, and it is the central argument of every debate on the growth of finite resources.

1020304050607080100200300400500× 2 in 35 years× 4 in 70 yearsyearsindex

Exercise 8: Five statements to correct

Each of the following five statements is FALSE. Say why and give the correct statement.

  • 1) "The unemployment rate went from 8% to 6%, so it fell by 2%."
  • 2) "Tuition rises by 4% per year; in ten years it will have risen by 40%."
  • 3) "My salary went from 45,000 to 60,000 dollars in fifteen years: I gained 33% in purchasing power."
  • 4) "The price index went from 120 to 150, so it rose by 30%."
  • 5) "Region A has a crude death rate half that of region B: people live twice as long there."

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  • 1) FALSE: 22 POINTS lower, that is −25%-25\% in relative terms
  • 2) FALSE: 1.0410≈1.48021.04^{10}\approx 1.4802, that is +48.0%+48.0\% and not 40%40\%
  • 3) FALSE: the prices are missing; 1.3331.40≈0.952\dfrac{1.333}{1.40}\approx 0.952, a LOSS of 4.8%4.8\%
  • 4) FALSE in percent: 3030 index points, that is +25%+25\% over the period and +50%+50\% since the base
  • 5) FALSE twice over: a crude rate follows the age structure, and it is not the inverse of a lifespan
1)

FALSE, or at least ambiguous to the point of being false. The decrease is 2 percentage POINTS, and in percent it is 6−88=−25%\dfrac{6-8}{8}=-25\%. Writing "fell by 2%" suggests the second reading and gives a number twelve times too small. Correct statement: the unemployment rate fell by two points, from 8% to 6%, a relative decrease of 25%.

2)

FALSE. Rates compound: 1.0410≈1.48021.04^{10}\approx 1.4802, an increase of 48.0% and not 40%. The gap of eight points comes from the fact that each increase applies to an amount that has already risen. Correct statement: at 4% per year, tuition rises by about 48% in ten years, and adding the rates is only a valid approximation over two or three periods.

3)

FALSE, the prices are missing. The nominal increase is 60,00045,000=1.333\dfrac{60{,}000}{45{,}000}=1.333, that is 33%; but if the price index has risen by 40% over the period, purchasing power is 1.3331.40≈0.952\dfrac{1.333}{1.40}\approx 0.952, a LOSS of 4.8%. Correct statement: the nominal salary rose by 33%, and purchasing power can only be computed by dividing this multiplier by that of the price index.

4)

FALSE if we speak in percent, true if we speak in index points. The index gained 30 INDEX POINTS, which corresponds to an increase of 150−120120=0.25\dfrac{150-120}{120}=0.25, that is 25%. The confusion comes from the fact that an index number looks like a percentage without being one. Correct statement: the index goes from 120 to 150, which represents a price increase of 25% relative to the previous period, and of 50% relative to the base year.

5)

FALSE twice over. First, a crude rate depends mostly on the age structure: region A is probably younger, and standardization would bring the gap down to almost nothing. Second, a death rate is not the inverse of a lifespan: life expectancy is computed from the age-specific rates in a life table, and a crude rate half as large never corresponds to a doubled life expectancy. Correct statement: crude rates cannot be compared between populations with different structures; they must be standardized, and to speak about lifespan you have to go through life expectancy.

Exercise 9: Problem: twenty years of teacher salary

The complete case, the one that comes back in every debate on collective agreements. A starting salary goes from 48,000 dollars in 2005 to 68,000 dollars in 2025, while the price index goes from 100 to 150.

  • a) Compute the nominal increase in percent, then the real increase.
  • b) The union asks for full catch-up. What salary is needed, and what increase does that represent?
  • c) The employer offers 3% per year for three years, with expected inflation of 2.2% per year. Will purchasing power be restored after the three years?
  • d) How many years at 3% against 2.2% would it take to erase the loss completely?
  • e) The employer's release announces "a cumulative increase of 9.3% over three years". Check it and comment on the choice of the word cumulative.

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  • a) Nominal +41.7%+41.7\%; real 1.41671.50≈0.944\dfrac{1.4167}{1.50}\approx 0.944, that is −5.6%-5.6\%
  • b) 72,00072{,}000 dollars, that is +5.9%+5.9\% from 68,00068{,}000
  • c) No: 1.09271.0675≈1.0236\dfrac{1.0927}{1.0675}\approx 1.0236, so 0.96670.9667 overall, still 3.3%3.3\% below 2005
  • d) ln⁡1.0588ln⁡1.00783≈7.3\dfrac{\ln 1.0588}{\ln 1.00783}\approx 7.3 years, at constant inflation
  • e) 1.033=1.09271.03^{3}=1.0927, that is 9.27%9.27\%: exact, and it is the largest of the five possible figures
a)

NOMINAL increase: 68,000−48,00048,000=20,00048,000≈0.4167\dfrac{68{,}000-48{,}000}{48{,}000}=\dfrac{20{,}000}{48{,}000}\approx 0.4167, that is 41.7%. REAL increase: multiplier of the salary divided by multiplier of prices, 1.41671.50≈0.9444\dfrac{1.4167}{1.50}\approx 0.9444, a 5.6% DECREASE in purchasing power. Both figures are exact and tell opposite stories: that is exactly why the two sides of a negotiation each quote their own.

b)

Full catch-up: 48,000×1.50=72,00048{,}000\times 1.50=72{,}000 dollars. From 68,000, this represents 72,000−68,00068,000≈0.0588\dfrac{72{,}000-68{,}000}{68{,}000}\approx 0.0588, an increase of 5.9%. Note the asymmetry already met: the loss is 5.6% and the catch-up requires 5.9%, because the two percentages are not computed on the same base.

c)

Multiplier of the salary over three years: 1.033≈1.09271.03^{3}\approx 1.0927. Multiplier of prices: 1.0223≈1.06751.022^{3}\approx 1.0675. Purchasing power: 1.09271.0675≈1.0236\dfrac{1.0927}{1.0675}\approx 1.0236, a gain of 2.4% over three years. Purchasing power therefore rises, but it does not make up the loss: starting from 0.9444, we reach 0.9444×1.0236≈0.96670.9444\times 1.0236\approx 0.9667, still 3.3% below the 2005 level.

d)

Each year, purchasing power is multiplied by 1.031.022≈1.00783\dfrac{1.03}{1.022}\approx 1.00783. We must solve (1.00783)n=10.9444=1.0588\left(1.00783\right)^{n}=\dfrac{1}{0.9444}=1.0588, so n=ln⁡1.0588ln⁡1.00783≈0.057160.007800≈7.3n=\dfrac{\ln 1.0588}{\ln 1.00783}\approx \dfrac{0.05716}{0.007800}\approx 7.3 years. It would therefore take more than seven years at this pace to return to the purchasing power of 2005, assuming inflation stays at 2.2%, which is the most fragile assumption of the whole calculation.

e)

Check: 1.033=1.0927271.03^{3}=1.092727, that is 9.27%, rounded to 9.3%. The figure is therefore exact. The word "cumulative" is technically correct, since it does designate the compounded effect of the three increases, and it is shrewd in negotiation, because it is the largest of the available figures to describe the same offer: one could have said 3% per year, or 9.0% by simple addition, or 2.4% real gain, or even a residual loss of 3.3% relative to 2005. Five exact numbers for a single offer: the lesson of the chapter is that a news release is judged by the choice of indicator, not by the accuracy of the calculation.

48200568202545.320252005 dollarscurrent dollars

Exercise 10: Problem: reading an economic news release

Excerpt: "Inflation slows to 2.4% in March, after 3.1% in February. The unemployment rate falls to 5.8%, its lowest level in two years. Gross domestic product per capita grew by 1.2% over one year. Wage growth reaches 4.0%."

  • a) "Inflation slows": have prices fallen? Explain the difference between inflation, disinflation and deflation.
  • b) Is the purchasing power of employees rising? Do the calculation.
  • c) Gross domestic product per capita grew by 1.2% while the population grew by 1.8%. What was the growth of total gross domestic product?
  • d) "Its lowest level in two years": what information is missing to judge?
  • e) Write the paragraph you would publish instead, in two or three sentences.

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  • a) No: +2.4%+2.4\% over one year, it is DISINFLATION; deflation would be a negative rate
  • b) 1.0401.024≈1.0156\dfrac{1.040}{1.024}\approx 1.0156, a gain of 1.6%1.6\%
  • c) 1.012×1.018≈1.03021.012\times 1.018\approx 1.0302, that is about 3.0%3.0\%
  • d) The complete series, the margin of error of the survey, and the trend in the employment rate
  • e) Name what rises and what slows, bring each rate back to its base, point out what lies within the noise
a)

No, prices CONTINUE TO RISE, just more slowly: inflation of 2.4% means that the general price level is 2.4% higher than a year earlier. The move from 3.1% to 2.4% is called DISINFLATION, that is, a slowdown in the rise. DEFLATION is an actual fall in prices, hence a NEGATIVE rate, and it is a rare and dreaded phenomenon, because it encourages people to postpone purchases. An index that goes from 130 to 134.0 and then to 137.2 illustrates inflation and disinflation at once: it keeps rising, by 3.1% and then by only 2.4%.

b)

Wages up 4.0%, prices up 2.4%: purchasing power is multiplied by 1.0401.024≈1.0156\dfrac{1.040}{1.024}\approx 1.0156, a gain of 1.6%. The naive subtraction would also give 1.6 points, which is here a good approximation because the rates are small; the gap between the two methods only appears in the third decimal. You should still keep the reflex of the quotient, because with two-digit rates the approximation becomes plainly wrong.

c)

Gross domestic product per capita is the ratio of total product to population: 1+g1.018=1.012\dfrac{1+g}{1.018}=1.012, so 1+g=1.012×1.018≈1.030221+g=1.012\times 1.018\approx 1.03022 and total growth is about 3.0%. This kind of conversion is crucial in public debate: total growth of 3% in a country whose population grows by 1.8% is only a gain of 1.2% per person, and the same growth in a country with a stable population would be 3%.

d)

The SERIES is missing. "Lowest level in two years" says neither where we are coming from, nor whether the decline is steady or erratic, nor above all whether the participation rate has moved: a fall in unemployment accompanied by a fall in the employment rate would signal discouragement rather than an improvement. The margin of error of the labour force survey is also missing, of the order of two tenths of a point, which can by itself explain a drop from 5.9% to 5.8%. Finally, the two-year window is a choice: over ten years, the same 5.8% might be a high level.

e)

"In March, prices are still 2.4% higher than a year earlier, against 3.1% in February: the rise is slowing but not reversing. With wages rising by 4.0%, purchasing power gains about 1.6% over one year. Total gross domestic product grows by about 3.0%, but with the population growing by 1.8%, the gain per person is limited to 1.2%. The unemployment rate falls by a tenth of a point to 5.8%, a movement of the same order as the margin of error of the survey, which will need to be confirmed by the trend in the employment rate." Three ideas: name what rises and what slows, bring each rate back to its base, and point out what cannot be distinguished from noise.

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Previous chapter Z scores, percentile ranks and the R score, 360-300 Next chapter Cross-tabulations, chi-square and association, 360-300

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